Y=3x2^x+1-12

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Solution for Y=3x2^x+1-12 equation: 



=3Y^2^Y+1-12

We move all terms to the left:

-(3Y^2^Y+1-12)=0

We get rid of parentheses

-3Y^2^Y-1+12=0

We add all the numbers together, and all the variables

-3Y^2^Y+11=0

We move all terms containing Y to the left, all other terms to the right

-3Y^2^Y=-11

Y=-11/1

Y=-11

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